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0=6i^2-30i+36
We move all terms to the left:
0-(6i^2-30i+36)=0
We add all the numbers together, and all the variables
-(6i^2-30i+36)=0
We get rid of parentheses
-6i^2+30i-36=0
a = -6; b = 30; c = -36;
Δ = b2-4ac
Δ = 302-4·(-6)·(-36)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*-6}=\frac{-36}{-12} =+3 $$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*-6}=\frac{-24}{-12} =+2 $
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